12x^2-320x+160=0

Solution for 12x^2-320x+160=0 equation:

12x^2-320x+160=0

a = 12; b = -320; c = +160;
Δ = b2-4ac
Δ = -3202-4·12·160
Δ = 94720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{94720}=\sqrt{256*370}=\sqrt{256}*\sqrt{370}=16\sqrt{370}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-16\sqrt{370}}{2*12}=\frac{320-16\sqrt{370}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+16\sqrt{370}}{2*12}=\frac{320+16\sqrt{370}}{24}
$